560=2x^2+3x

Solution for 560=2x^2+3x equation:

560=2x^2+3x

We move all terms to the left:

560-(2x^2+3x)=0

We get rid of parentheses

-2x^2-3x+560=0

a = -2; b = -3; c = +560;
Δ = b2-4ac
Δ = -32-4·(-2)·560
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-67}{2*-2}=\frac{-64}{-4}
=+16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+67}{2*-2}=\frac{70}{-4}
=-17+1/2
$